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### 2958. Moves improperly defined as deleted

Section: 22.3.2 [pairs.pair], 22.4.4.2 [tuple.assign] Status: C++20 Submitter: Casey Carter Opened: 2017-05-05 Last modified: 2021-02-25

Priority: 2

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Discussion:

LWG 2729 constrained many `pair` & `tuple` assignment operators to "not participate in overload resolution" and "be defined as deleted if." As discussed when LWG reviewed 2756, it is undesirable to require that a move constructor or assignment operator be "defined as deleted," since it is unclear whether that operation should be implicitly deleted, and therefore not participate in overload resolution, or explicitly deleted and therefore impede overload resolution for usages that would otherwise find copies.

[2017-07 Toronto Wed Issue Prioritization]

Priority 2

[2017-11 Albuquerque Wednesday issue processing]

Move to Immediate

Proposed resolution:

This wording is relative to N4659.

1. Edit 22.3.2 [pairs.pair] as indicated:

   >     pair& operator=(pair&& p) noexcept(see below);

   > > -21- Effects: Assigns to `first` with `std::forward<first_type>(p.first)` and to `second` with `std::forward<second_type>(p.second)`.

   > > -22- Remarks: This operator shall be defined as deleted not participate in overload resolution unless `is_move_assignable_v<first_type>` is `true` and `is_move_assignable_v<second_type>` is `true`.

   > > […]

2. Edit 22.4.4.2 [tuple.assign] as indicated:

   >     tuple& operator=(tuple&& u) noexcept(see below);

   > > -5- Effects: For all `i`, assigns `std::forward<Ti>(get<i>(u))` to `get<i>(*this)`.

   > > -6- Remarks: This operator shall be defined as deleted not participate in overload resolution unless `is_move_assignable_v<Ti>` is `true` for all `i`.

   > > […]