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### 2022. `reference_wrapper<T>::result_type` is underspecified

Section: 20.14.6 [refwrap] Status: C++11 Submitter: Daniel Krügler Opened: 2010-12-08 Last modified: 2016-01-28

Priority: Not Prioritized

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Discussion:

Issue 1295 correctly removed function types and references to function types from the bullet 1 of 20.14.4 [func.require] p. 3 because neither function types nor function references satisfy the requirements for a target object which is defined to be an object of a callable type. This has the effect that the reference in 20.14.6 [refwrap] p. 2

> `reference_wrapper` has a weak result type (20.8.2).

is insufficient as a reference to define the member type `result_type` when the template argument `T` is a function type.

There are basically two approaches to solve the problem:

1. Extend the definition of a weak result type in 20.14.4 [func.require] p. 3 to both function types and references thereof. This extension must be specified independend from the concept of a call wrapper, though.

2. Add one extra sentence to 20.14.6 [refwrap] p. 2 that simply defines the member type `result_type` for `reference_wrapper<T>`, when `T` is a function type.

I checked the current usages of weak result type to have a base to argue for one or the other approach. It turns out, that there is no further reference to this definition in regard to function types or references thereof. The only other reference can be found in 20.14.15.4 [func.bind.bind] p. 3, where `g` is required to be a class type.

[2011-02-23 Reflector discussion]

Moved to Tentatively Ready after 5 votes.

Proposed resolution:

The suggested wording changes are against the working draft N3242.

1. Change 20.14.6 [refwrap] p. 2 as indicated:

   > 2 `reference_wrapper<T>` has a weak result type (20.8.2). If `T` is a function type, `result_type` shall be a synonym for the return type of `T`.