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### 2952. `iterator_traits` should work for pointers to cv `T`

Section: 23.3.2.3 [iterator.traits] Status: C++20 Submitter: Billy Robert O'Neal III Opened: 2017-03-27 Last modified: 2021-02-25

Priority: 0

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Discussion:

`iterator_traits` accepts pointer to `volatile T*`, but then says that the `value_type` is `volatile T`, instead of `T`, which is inconsistent for what it does for pointer to `const T`. We should either reject `volatile` outright or give the right answer.

[2017-03-30, David Krauss comments]

`volatile` pointers may not be well-behaved random-access iterators. When simple access incurs side effects, the multiple-pass guarantee depends on underlying (hardware) semantics.

[2017-07 Toronto Wed Issue Prioritization]

Priority 0; move to Ready

Proposed resolution:

This wording is relative to N4659.

1. Change 23.2 [iterator.synopsis] as indicated:

   >     // 23.4 [iterator.primitives], primitives
   >     template<class Iterator> struct iterator_traits;
   >     template<class T> struct iterator_traits<T*>;
   >     template<class T> struct iterator_traits<const T*>;

2. Change 23.3.2.3 [iterator.traits] as indicated:

   > -3- It is specialized for pointers as

   > >     namespace std {
   > >       template<class T> struct iterator_traits<T*> {
   > >         using difference_type = ptrdiff_t;
   > >         using value_type = remove_cv_t<T>;
   > >         using pointer = T*;
   > >         using reference = T&;
   > >         using iterator_category = random_access_iterator_tag;
   > >       };
   > >     }

   > and for pointers to `const` as

   > >     namespace std {
   > >       template<class T> struct iterator_traits<const T*> {
   > >         using difference_type = ptrdiff_t;
   > >         using value_type = T;
   > >         using pointer = const T*;
   > >         using reference = const T&;
   > >         using iterator_category = random_access_iterator_tag;
   > >       };
   > >     }